Question

Pls help me solve this

Answer 1

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Answer 2

In triangle CAD , angle A + angle CDA + y = 180 (asp of a triangle)
so by solving that y=45°

angle CDA+angle CDB = 180 (LP)
so angle CDB=95
now in triangle CDB
40+X+95=180
=> x=45°

so X = Y = 45°