Question

pls help me to find ans​

Answer 1

Using the equation S=1/2gt^2

S=1/2×9.8×3×3

S=44.1m

Now using v^2-u^2=2AS

V^2-0=2×9.8×44.1

It's a freely falling body so it's acceleration will be due to gravity ie 9.8 m/s ans I have considered initial velocity to be 0

V^2=864.36

V=29.4m/s

Answer 2

Answer:

I can solve this problem.

ok

t = 3s , g = -9.8m/s^2

By kinematic equation

v = gt

v = -9.8 × 3

v = -29.4m/s

As the body is falling down , so it's acceleration will be -9.8m/s^2. As there is acceleration due to gravity on the body.

Ans . it's velocity = -24m/s and acceleration = -9.8m/s^2

Solved by my own logical proof.

Remember : - ive sign indicates object is falling down.

Thank you

From

:-(:-(:-♧Amannn♧