pls help me to slove this sum (‘_’)(;_:)
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yuvrajkj:
prerna here d^2 will give a negative value
Answers
Answered by
2
let the numbers be a-d, a, a+d
sum = (a-d) + a + (a+d)
3a = 2
a = 2/3
Product = a x a-d x a+d
=> 2/3 x (4/9 - d^2) = 440
=> (4/9 - d^2) = 660
=> Here d^2 will give a negative value.
which is not possible.
Thus it has no solution.
Please enlighten me if I have missed something!
sum = (a-d) + a + (a+d)
3a = 2
a = 2/3
Product = a x a-d x a+d
=> 2/3 x (4/9 - d^2) = 440
=> (4/9 - d^2) = 660
=> Here d^2 will give a negative value.
which is not possible.
Thus it has no solution.
Please enlighten me if I have missed something!
Answered by
1
Ok I can help you if it is -2 or -440
factors of 440 = 2 x 2 x 2 x 5 x 11
so numbers -8 -5 and 11
-8 + -5 + 11 = -2
-8 x -5 x 11 = 440
if numbers are 8, 5, -11
8 + 5 + -11 = 2
8 x 5 x -11 = - 440
Hope it will help you. Better than nothing
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