Question

Pls help me to solve (b)​

Answer 1

Answer:

a³ + b³ + c³ -3abc

=a³ + (b³ + c³) -3abc

Given that

a+ b + c =0 => b+c = -a

On substituting b+c=-a we get

= a³ + (b +c)³ -3bc(b+c) -3abc

= a³ + (b+c)³ -3bc(-a) -3abc

= a³ + (b + c)³ +3abc -3abc

We know that  x³ + y³ = (x + y)(x² + y² -xy )

Hence the above equation becomes

= {a + (b + c)}{a² + (b+c)² -a(b + c)}

=(a + b + c)(a² + b² + c² + 2bc – ab – ac)

 

Step-by-step explanation:

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