pls help me to solve this question
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Hi friend here is your answer
____________________________________
Given data
Resistance -- 1.5 ohm
Length -- 80cm = 80 * 10^-2
Area of cross section -- 0.025 CM sq
= 0.025 * 10^-4m sq
_________________________________
Solution
(Specific resistance is also known as Resistivity )
We know that
Resistivity = Resistance*Area / Length
= 1.5 * 0.025*10^-4 / 80*10^-2
= 4.6875 * 10^-6 ohm-meter
Hence the resistivity or the specific resistance of wire is 4.6875 * 10^-6 ohm-meter
_________________________________
Hope it helps you...........!!
#TheUsos
Down since
Day One Ish
____________________________________
Given data
Resistance -- 1.5 ohm
Length -- 80cm = 80 * 10^-2
Area of cross section -- 0.025 CM sq
= 0.025 * 10^-4m sq
_________________________________
Solution
(Specific resistance is also known as Resistivity )
We know that
Resistivity = Resistance*Area / Length
= 1.5 * 0.025*10^-4 / 80*10^-2
= 4.6875 * 10^-6 ohm-meter
Hence the resistivity or the specific resistance of wire is 4.6875 * 10^-6 ohm-meter
_________________________________
Hope it helps you...........!!
#TheUsos
Down since
Day One Ish
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