Question

pls help me to solve this
those who will solve two questions will be marked as brainlliest.

Answer 1

Let rate of my walk = P km/h
and intial time = Q hours

we know,
speed = distance/time taken

initally /
speed = distance/time
P = 2/Q ------(1)

now, speed increase 1 km/h .
e.g my new speed of walk = (P +1) km/h
after increasing speed time taken to cover 2km is 10 min less .
e.g new time = (Q - 10/60) hours
= ( Q - 1/6) hrs

speed = distance/ time
(P +1) = 2/(Q - 1/6) -----(2)

put eqn (1) value In eqn (2),

2/Q + 1 = 2/(Q - 1/6)
1 = 2/(Q - 1/6) - 2/Q
= 2{ Q - Q + 1/6}/Q(Q - 1/6)
= 2×1/6/(Q² - Q/6)
= 2/(6Q² - Q)

6Q² -Q - 2 = 0
6Q² +3Q - 4Q -2 = 0
3Q(2Q +1) -2(2Q + 1) =0
(3Q -2)(2Q +1) = 0
Q = 2/3 and -1/2
but time never will be negative so,
Q = 2/3
put In eqn (1)
P = 2/(2/3) = 3 km/h

hence, rate of walk = 3km/h

Answer 2

Answer:

above is your some answer

I hope it's help you