Pls help me with the (B) part
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mene dono b Vale question kr diye hai....
tumhe jiska answer chahiye vo dekh Lena...
first answer is 130° and second answer is 85° .......
hope this helps...
if correct....
mark as brainlist plzz...
tumhe jiska answer chahiye vo dekh Lena...
first answer is 130° and second answer is 85° .......
hope this helps...
if correct....
mark as brainlist plzz...
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HERE IS YOUR SOLUTION;
◆ Given: PQ||RS & Angle MXQ = 135° & Angle MYR = 40°.
◆ To Find: Angle XMY = ?
◆ Construction: Draw a line MB || PQ || RS.
◆ Solution:
We know that;
Angle MXQ + Angle XMB = 180°
【Angles on the same side of the transversal are supplimentry】
=> 135° + Angle XMB = 180°
=> Angle XMB = 45° --------1)
Now,
Angle MYR = Angle YMB
【Alternate Angles】
=> Angle YMB = 40° -------2)
Now,
Angle XMY = Angle XMB + Angle BMY
Therefore, by adding eq" 1) & 2), we get;
Angle XMY = 40° + 45°
=> Angle XMY = 85°
◆ So, Angle XMY is 85° ◆
HOPE IT HELPS
◆ Given: PQ||RS & Angle MXQ = 135° & Angle MYR = 40°.
◆ To Find: Angle XMY = ?
◆ Construction: Draw a line MB || PQ || RS.
◆ Solution:
We know that;
Angle MXQ + Angle XMB = 180°
【Angles on the same side of the transversal are supplimentry】
=> 135° + Angle XMB = 180°
=> Angle XMB = 45° --------1)
Now,
Angle MYR = Angle YMB
【Alternate Angles】
=> Angle YMB = 40° -------2)
Now,
Angle XMY = Angle XMB + Angle BMY
Therefore, by adding eq" 1) & 2), we get;
Angle XMY = 40° + 45°
=> Angle XMY = 85°
◆ So, Angle XMY is 85° ◆
HOPE IT HELPS
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