Question

pls help me!!! with this​

Answer 1

Equivalent Resistance:

If we attach many resistors to the same circuit, it can get complicated to find the voltage drop and current through each resistor. We can find the equivalent resistance to simplify a circuit.

Imagine replacing the entire collection of resistors with a single resistor that results in the same voltage drop and total current delivered as the collection of resistors. The resistance of this imaginary resistor is the equivalent resistance of the circuit, ReqReq.

There are two rules for finding equivalent resistance, for resistors in series and parallel. If several resistors are in series, we simply add up the resistances.

Req=R1+R2+R3+...Req=R1+R2+R3+...

If the resistors are in parallel, we need to use a different formula:

1Req=1R1+1R2+1R3+...1Req=1R1+1R2+1R3+...

This allows us to find the equivalent resistance of a small part of the circuit, where all the resistors are connected in the same way. Once we have done this, we can treat that section of the circuit as a single resistor and use it in another calculation to find the equivalent resistance of a larger section of the circuit. We can keep doing this until we have the equivalent resistance of the entire circuit.

Answer and Explanation:

The answer is 15 ΩΩ.

This network consists of a top section and a bottom section. Let's find the equivalent resistance of the top...

Answer 2

Answer:

There are two types connection one is series and another is parallel.

Explanation:

In this diagram first find in series connection.

        = 1Ω+1Ω+1Ω+1Ω+1Ω=5Ω

Connection parallel =

                                              R= 1/R1+1/R2

                                              R= 1/1+1/1

                                               R=1+1/2

                                              R= 1Ω

          Total Resistance= 5Ω+1Ω

                                        =6Ω