Question

Pls help me with this I ve got my exams

Answer 1

Answer:

0,-1,2

Step-by-step explanation:

(x^2-x+1)(x+1)-(x+1)(x+1)=0

(x^3+x^2-x^2-x+x+1)-(x^2+1+2x)=0

(x^3+1)=x^2+1+2x

x^3=x^2+2x

x^3-x^2-2x=0

(x)(x^2-x-2)=0

(x)(x^2-2x+x-2)=0

(x)[x(x-2)+1(x-2)]=0

(x)(x+1)(x-2)=0

thus x=0,-1,2

hope it helps u

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