Question

Pls help me with this


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Answer 1

Diagonal of square = √2 × side

=

3 - x

= √2 ×

1

(x + 1)

√2 2

⇒ 3 - x = √2 × √2 ×

1

(x + 1)

2

⇒ 3 – x = x + 1

⇒ x + x = 3 –1

⇒ 2x = 2 ⇒ x = 1 unit

Answer 2

Step-by-step explanation:

$\huge \mathfrak \pink {Ꭺŋѕwєr}$

$diagonal = \sqrt{2} \times side$

$= \sqrt{2} \times \frac{1}{2} (x + 1)$

$= \frac{3 - x}{ \sqrt{2} }$

$= x + 1 = 3 - x$

$x = 1$