Question

pls help me with this question ​

Answer 1

Answer:

1. +8/3

2. +2

3.+2

4.-1

5.+3

6. +5

Answer 2

Explanation:

To Find -

• Oxidation number of underlined elements

1)

Pb3O4

Let x be the O.N. of Pb

Then,

→ 3x - 2×4 = 0

→ 3x = 8

→ x = +8/3

2)

MnSO4

Let x be the O.N. of Mn

Then,

→ x + 6 - 2×4 = 0

→ x = +2

3)

K2MnO4

Let x be the O.N. of Mn

Then,

→ 1×2 + x - 2×4 = 0

→ x = +6

4)

NH4+

Let x be the O.N. of N

Then,

→ x + 1×4 = 1

→ x = -3

5)

S2O3

Let x be the O.N. of S

Then,

→ 2x - 2×3 = 0

→ 2x = 6

→ x = +3

6)

HNO3

Let x be the O.N. of N

Then,

→ 1 + x - 2×3 = 0

→ x = +5