Question

pls help photo is above​

Answer 1

Simplify

$\sf \dfrac{3}{4} + \dfrac{5}{2} {\left[ \begin{array}{c} \dfrac{1}{4} + {\huge\{} \dfrac{2}{5} - {\huge(} \dfrac{1}{5} \div \dfrac{2}{15} \times \dfrac{1}{10} \huge{)} \} \end{array} \right]}$

Answer

2 is the required answer.

Solution

We know that here we are given with a equation which seems to be quite complex because of the use of certain braces and mathematical operations but what if they are solved by a simplified and organized way i.e the method of BODMAS will be used here.

$\footnotesize{ ↦\dfrac{3}{4} + \dfrac{5}{2} {\left[ \begin{array}{c} \dfrac{1}{4} + {\huge\{} \dfrac{2}{5} - {\huge(} \dfrac{1}{5} \div \dfrac{2}{15} \times \dfrac{1}{10} \huge{)} \} \end{array} \right]}}$

First we will solve the equation enclosed by round braces ( ) ;

$\footnotesize{ ↦\dfrac{3}{4} + \dfrac{5}{2} {\left[ \begin{array}{c} \dfrac{1}{4} + {\huge\{} \dfrac{2}{5} - {\huge(} \dfrac{1}{ \cancel5} \times \dfrac{ \cancel{15}}{2} \times \dfrac{1}{10} \huge{)} \} \end{array} \right]}}$

$\footnotesize{ ↦\dfrac{3}{4} + \dfrac{5}{2} {\left[ \begin{array}{c} \dfrac{1}{4} + {\huge\{} \dfrac{2}{5} - \dfrac{3}{20} \huge{} \} \end{array} \right]}}$

$\footnotesize{ ↦\dfrac{3}{4} + \dfrac{5}{2} {\left[ \begin{array}{c} \dfrac{1}{4} + {\huge\{} \dfrac{8 - 3}{20} \huge{} \} \end{array} \right]}}$

$\footnotesize{ ↦\dfrac{3}{4} + \dfrac{5}{2} {\left[ \begin{array}{c} \dfrac{1}{4} + {\huge\{} \cancel\dfrac{5}{20} \huge{} \} \end{array} \right]}}$

$\footnotesize{ ↦\dfrac{3}{4} + \dfrac{5}{2} {\left[ \begin{array}{c} \dfrac{1}{4} +\dfrac{1}{4} \end{array} \right]}}$

$\footnotesize{ ↦\dfrac{3}{4} + \dfrac{5}{2} {\left[ \begin{array}{c} \cancel\dfrac{2}{4} \end{array} \right]}}$

$\footnotesize{ ↦\dfrac{3}{4} + \dfrac{5}{2} {\left[ \begin{array}{c} \dfrac{1}{2} \end{array} \right]}}$

$\footnotesize{ ↦ \cancel\dfrac{8}{4} } = \large{ \bf \red2}$

Hence, we are done with our calculation !!

$\underline{\rule{190pt}{2pt}}$

Note

You might solve the equations by dividing the equation into three parts with the help of braces , once you solve one brace restore its answer and solve other but do solve mathematical operations as per their order.

Thankyou