Math, asked by roychoudhurymoli, 4 months ago

pls help question number 5,6,7,8 and 9​

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Answers

Answered by rakeshverma0509
0

Answer:

if you know the formula of questions then it is

easy to di this.......

Do you know the formula .Of all questions.....


roychoudhurymoli: no
roychoudhurymoli: that is why I am asking
rakeshverma0509: ok
rakeshverma0509: as your wish
rakeshverma0509: ☺️☺️☺️☺️
Answered by nefqriiouslady
2

Step-by-step explanation:

6) (edge)³ = (8)³ = 8×8×8 = 512 cm²

TSA= 6(edge)² =6×(8)³ =384 cm² (for 6 ii just convert meters into cm and follow the same thing like 6 i)

7) =sides³ =216cm³

=> side = ³√216= 6cm (follow same method for 7ii)

8)L= 24cm

B= 18cm

H=4cm

volume of cuboid = l×b×h= 1728cm³

9) It is given that

Length of the wall 900cm

Height of the hall 600cm

Breadth of the wall 20cm

We know that

Volume of the wall 900×600×20cm³= 10800000cm³

Volume of one Brick 30× 15× 10= 4500cm³

So we get

Number of bricks required to construct the wall =

10800000/4500 = 2400


roychoudhurymoli: no. 5?
nefqriiouslady: oh.. sorry 6th one is actually 5th's answer and I missed 6th question....
nefqriiouslady: no no, I actually missed 7th one..
nefqriiouslady: anyways, now you know the formula right? just apply the formula and solve ;)
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