Question

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Answer 1

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Answer 2

Answer:

1/2   at alpha = 45 degree

Step-by-step explanation:

Find Maxima of Sin alpha . sin Beta

let alpha =x

say F(x) = Sin x . sin ( 90-x)

=  Sin X. Cos X

= 1/2 Sin2x

F'= 1/2 .2 Cos2X

= Cos 2X = 0 for Critical Points

2X= 90 degrees

x= 45 Degrees

F" = -2sin2x = -2(1)=-2 ... so its Maxima

Value of F(x) at X=45 degrees = sin45.cos45 = 1/√2 x 1/√2 = 1/2