Question

pls help trigonometry

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Answer 1

Answer:

Remember that 1-sin2x = cos2x

So if you multiply this fraction (cosx)/(1-sinx) by (1+sinx)/(1+sinx) you will get:

(cosx)(1+sinx)/(1-sin2x) = (cosx)(1+sinx)/(cos2x) or (1+sinx)/(cosx)

or: 1/cosx + sinx/cosx = secx + tanx.

Step-by-step explanation:

i hope this will help you

Answer 2

Answer....

hope it will help you

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