Math, asked by suhas122006, 3 months ago

PLS HELP (With Step By Step)​

Attachments:

Answers

Answered by Anonymous
7

Answer:

This implies that

x2+2ax=4x−4a−13

or

x2+2ax−4x+4a+13=0

or

x2+(2a−4)x+(4a+13)=0

Since the equation has just one solution instead of the usual two distinct solutions, then the two solutions must be same i.e. discriminant = 0.

Hence we get that

(2a−4)2=4⋅1⋅(4a+13)

or

4a2−16a+16=16a+52

or

4a2−32a−36=0

or

a2−8a−9=0

or

(a−9)(a+1)=0

So the values of a are −1 and 9.

Answered by Talentedgirl1
1

Answer:

S is not equivalence relation but R is not an equivalence relation

Step-by-step explanation:

The step by step explanation is the above picture...

Hope it helps you

Attachments:
Similar questions