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Answers
Answer:
1
10 days
20 days
40 days
None of these
Answer :
A
Solution :
(a)
<br> Also
2
Let ym be the height of the wall at which the ladder touches. Also, let the foot of the ladder be xm away from the wall.
Then, by Pythagoras theorem, we have:
x
2
+y
2
=25 [Length of the ladder =5m]
⇒y=
25−x
2
Then, the rate of change of height (y) with respect to time (t) is given by,
dt
dy
=
25−x
2
−x
⋅
dt
dx
It is given that
dt
dx
=2cm/s
∴
dt
dy
=
25−x
2
−2x
Now, when x=4m, we have:
dt
dy
=
25−4
2
−2×4
=−
3
8
Hence, the height of the ladder on the wall is decreasing at the rate of
3
8
cm/s.
Step-by-step explanation:
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can not be predicted exactly for any single nucleus. -can only ... Average number of radioactive decays per unit time (rate) ... Half- life: time required to decay a sample to 50% of its initial quantity.
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