Question

PLS HELPPP
The graph shows two lines, K and J.


A coordinate plane is shown. Two lines are graphed. Line K has the equation y equals 2x minus 1. Line J has equation y equals negative 3 x plus 4.

Based on the graph, which statement is correct about the solution to the system of equations for lines K and J? (4 points)


A-(1, 1) is the solution to both lines K and J.

B-(−1, 0) is the solution to line K but not to line J.

C-(1, 1) is the solution to line K but not to line J.

D-(0, 4) is the solution to both lines K and J.

Answer 1

Answer:

1,1 is answer because it lies in the ist quadrant where

Answer 2

Answer:

Answer is A since both the lines intersect at point (1,1) that is to say that any condition at point (1,1) is true for both- line K & J.

if u wanna solve using the quardratic method then

K is y= 2x - 1. J is Y= (-3x) + 4

putting both y equal(or putting J in K) u get

::::(-3x) +4= 2x - 1

::::x= 1. //putting x in either eqn //

(eqn K). Y= 2x -1.

:::::y= 2*1 - 1

:::::y= 1

so X=1 & Y=1 hence (1,1) is correct