Question

If x=−1, y=2, z=−3 find the value of −x3y2z + 2y2z2 − 7xyz + 3x2y2

Answer 1

Answer:

0

Step-by-step explanation:

-x³y²z + 2y2z² - 7xyz + 3x2y²

= -(-1)(2)(-3) +2(2)[2(-3)²] - 7(-1)(2)(-3) + 3(-1)[2(2)²]

= -6 +72 -42 -24

= 72-72

= 0

HOPE IT HELPS YOU:)

Answer 2

Answer:

0

Step-by-step explanation:

-x³y²z + 2y2z² - 7xyz + 3x2y²

= -(-1)(2)(-3) +2(2)[2(-3)²] - 7(-1)(2)(-3) + 3(-1)[2(2)²]

= -6 +72 -42 -24

= 72-72

= 0