Question

pls hlp me
steps needed
will mark u as brainliest​

Answer 1

Answer:

HI FRIEND MARK IT AS BRAiNLIEST

Step-by-step explanation:

LET US USE THE FORMULA (A+B)²

(-4+√48)²=16+48+2×-4×√48

                =64-32√3

(-4-√48)²=16+48+2×-4×√48

               =64-32√3

THEN ADD BOTH

                      =64

HOPE IT HELPS

THANK AND FOLLOW ME

Answer 2

✿$\underline{\textbf{\textsf{\purple{Solution}:-}}}$

$\longrightarrow \sf \left(-4+\sqrt{48}i\right)^2 + \left(-4 - \sqrt{48}i\right)^2$

As we know that ,

◉ $\rm i = \sqrt{-1}$

Substituting we have ,

$\sf\longrightarrow \Big[-4+\sqrt{48}\sqrt{-1}\Big]^2+\Big[-4-\sqrt{48}\sqrt{-1}\Big]^2$

$\sf\longrightarrow \Big[(-4)^2 + (\sqrt{48})^2(\sqrt{-1})^2\Big]+\Big[(-4)^2-(\sqrt{48})^2(\sqrt{-1})^2\Big]$

$\sf \longrightarrow \Big[16+48(-1)\Big]+\Big[16-48(-1)\Big]$

$\sf\longrightarrow 16 - 48 + 16 + 48$

$\sf\longrightarrow 16 + 16$

$\longrightarrow \boxed{\textbf{\textsf{\green{32}}}}$

$\therefore$ Hence , ( - 4 + √48 i)² + ( - 4 - √48 i)² = 32