Question

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Answer 1

Explanation:

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Answer 2

Explanation:

(i) 1 mole of carbon is burnt in air.

C+O2

→CO2

1 mole of C produces 1 mole of CO

2

which corresponds to 44 g of CO

2

(ii) 1 mole of carbon is burnt in 16 g of dioxygen.

16 g of dioxygen corresponds to

=0.5 moles.

Here, dioxygen is the limiting reagent.

It will produce 0.5 moles of CO2

which corresponds to 0.5×44=22 g of CO2

(iii) 2 moles of carbon are burnt in 16 g of dioxygen.

16 g of dioxygen corresponds to

16/32=0.5 moles