Question

pls I want solution with figure pls sove this question

Answer 1

wht is the 4rt line?

Answer 2

Let AB as tree.

where,AC is perpendicular to QC

angleAQP=beta

angleAPB=alpha

BP=a

QB=b

BC=x

AC=h


in ∆ACP,

tan alpha=AC/PC

tan alpha=h/x+a

x+a=h/tan alpha

x=(h/tan alpha)-a...........i


in ∆ACQ

tan beta=AC/QC

tan beta=h/x+b

x=(h/tan beta)-b


[sol with fig is in attachment]