pls I want solution with figure pls sove this question
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astha42:
pls solve some one
hiii
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wht is the 4rt line?
(b-a) tan alfa tan bita /tan alfa - tan bita
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Let AB as tree.
where,AC is perpendicular to QC
angleAQP=beta
angleAPB=alpha
BP=a
QB=b
BC=x
AC=h
in ∆ACP,
tan alpha=AC/PC
tan alpha=h/x+a
x+a=h/tan alpha
x=(h/tan alpha)-a...........i
in ∆ACQ
tan beta=AC/QC
tan beta=h/x+b
x=(h/tan beta)-b
[sol with fig is in attachment]
where,AC is perpendicular to QC
angleAQP=beta
angleAPB=alpha
BP=a
QB=b
BC=x
AC=h
in ∆ACP,
tan alpha=AC/PC
tan alpha=h/x+a
x+a=h/tan alpha
x=(h/tan alpha)-a...........i
in ∆ACQ
tan beta=AC/QC
tan beta=h/x+b
x=(h/tan beta)-b
[sol with fig is in attachment]
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ohhh helo pranjal this question belongs to me and why u replying to him
what
i mark him brainliest
thanks
now why r u saying thanks
ooo
tu thoda khiska hua he kya
are yr bus kr
hmmm thik he bye
bye
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