Question

Pls i will give you a all mny​

Answer 1

Answer:

HOPE THE ATTACHMENT HELPS YOU

Answer 2

Step-by-step explanation:

ANSWER 1.

GIVEN THAT :

$g(x) = 2x - 1$

we know that

$g(x) = 0$

so

$2x - 1 = 0 \\ \\ 2x = 1 \\ x = \frac{1}{2}$

ANSWER 2

${x}^{3} + {y}^{3} + {z}^{3} = 3xyz$

BY USING THIS IDENTITY

${16}^{3} + {( - 7)}^{3} + {( - 9)}^{3} \\ \\ \\ 3 \times 16 ( - 7) \times ( - 9) \\ \\ 3024$

ANSWER 3:

${( {1}^{3} + {2}^{3} + {3}^{3} }^{ \frac{1}{2} }$

${1 + 8 + 27)}^{ \frac{1}{2} } \\ \\ {36}^{ \frac{1}{2} } \\ \\ { {6}^{2} }^{ \frac{1}{2} } \\ \\ = 6$

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