pls integrate sin2x.cos3x
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⌠sin2x cos3xdx
=⌠2sinx cosx(4sin3x-3cosx)dx
=8⌠sinx cos4xdx - 6⌠sinx cosxdx
let cosx=t
or -sinxdx=dt
so, 8⌠(-t4)dt+6tdt
=6t2/2 - 8t5/5
=3cos2x-(8/5)cos5x+c (Ans)
=⌠2sinx cosx(4sin3x-3cosx)dx
=8⌠sinx cos4xdx - 6⌠sinx cosxdx
let cosx=t
or -sinxdx=dt
so, 8⌠(-t4)dt+6tdt
=6t2/2 - 8t5/5
=3cos2x-(8/5)cos5x+c (Ans)
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