Question

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Answer 1

Explanation:

1. initial velocity of A = 0

initial velocity of B = 30km/h

2. distance traveled by A = area of triangle OAB = (1/2)*15*20 = 150km

Dist travelled by B = area of triangle OCD = (1/2)*30*10= 150km

3. Both A and B have same velocity (10kmph) at T time

accln of A = 20/15 = 4/3km/hr^2

v = u + at

10 = 0 + (4/3)T

T = 30/4 = 7.5hr

Answer 2

Answer:

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