Question

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Answer 1

Answer:

Given:- Two zeroes of a polynomial are 5/4 and 3/2.

To find :- Unknown quadratic polynomial.

Solution:-

We know that the standard form of a quadratic polynomial is

k{x^2-(sum of zeroes)x+product of zeroes}...(1)

sum of zeroes= 5/4+3/2

= 11/2

product of zeroes= 5/4×3/2

= 15/8

now put these values in equation (1) we get,

k{x^2-(11/2)x+15/8}

so the quadratic polynomial is

x^2-11/2x+15/8

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Answer 2

Step-by-step explanation:

(alpha+beta) = sum of zeros= 5/4+3/2== 11/4

(alpha×beta)= products of zeros= 5/4×3/2==15/8

Now, put values :--

≈ x²-(alpha+beta) x + alpha×beta

≈ x²-(11/4)x+15/8. LCM = 8

≈ 8(x²-11/4x+15/8)= 8

≈ 8x²-22x+15 Ans .

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