Question

pls refer to the attatchment

Answer 1

Answer:

3.545..............

Answer 2

${\huge{\star}{\color{blue}{\rm{Answer}}}} \huge \star$

$=>\frac{7x - 1}{4} - \frac{1}{3} (2x - \frac{1 - x}{2} ) = \frac{10}{3} \\ \\ \\ => \frac{7x - 1}{4} - \frac{1}{3} \{ \frac{4x - (1 - x)}{2} \} = \frac{10}{3} \\\\ \\ =>\frac{7x - 1}{4} - \frac{1}{3} \{ \frac{4x - 1 + x}{2} \} = \frac{10}{3} \\ \\ \\ => \frac{7x - 1}{4} - \frac{1}{3} \{ \frac{5x - 1}{2} \} = \frac{10}{3} \\ \\\\ => \frac{7x - 1}{4} - \frac{(5x - 1)}{3 \times 2} = \frac{10}{3} \\ \\ =>\frac{7x - 1}{4} - \frac{ 5x + 1}{6} = \frac{10}{3} \\ \\ \\ =>\frac{3(7x - 1) - 2(5x + 1)}{12} = \frac{10}{3} \\ \\ \\ =>\frac{21x - 3 - 10x - 2}{12} = \frac{10}{3} \\ \\ \\ =>\frac{11x - 5}{12} = \frac{10}{3}$

Now we have to cross multiply both fractions

$11x-5(3)=10(12)$

$11x-15=120$

$11x=120-15$

$11x=105$

$\sf \large \boxed{ \purple{:\implies x = \frac{105}{11} }}$

Hope it helps

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