Question

Pls say me the ans fast​

Answer 1

EXPLANATION.

Graph of the equation,

(1) = 3x - 5 = 7.

(2) = x + 2 = 9.

(3) = 11y + 6 = -27.

From equation (1), we get.

(1) = 3x - 5 = 7.

⇒ 3x = 7 + 5.

⇒ 3x = 12.

⇒ x = 12/3.

⇒ x = 4.

Their Co-ordinates = (4,0).

From equation, (2) we get.

⇒ x + 2 = 9.

⇒ x = 9 - 2.

⇒ x = 7.

Their Co-ordinates = (7,0).

From equation (3), we get.

⇒ 11y + 6 = -27.

⇒ 11y = -27 - 6.

⇒ 11y = -33.

⇒ y = -3.

Their Co-ordinates = (0,-3).

Answer 2

$\large\underline\blue{\bold{Given \: Question :- }}$

Draw the graph of the following equations :-

(1) 3x - 5 = 7

(2) x + 2 = 9

(3) 11y + 6 = - 27

$\huge \blue{AηsωeR} ✍$

$\bf \:\large \red{AηsωeR : 1.} ✍$

☆The equation of line is

$\bf \:  ⟼ 3x - 5 = 7$

$\blue{\bold{\bf \:  ⟼ 3x = 12}}$

$\blue{\bold{\bf \:  ⟼ x = 4}}$

First, we find coordinates of points, which are lies in the line, in both x-axis & y-axis, which represents the graph structure.

➣ To calculate the coordinates of points, which are lies on the line, are shown in the below table.

$\begin{gathered}\boxed{\begin{array}{cccc}\bf x & \bf y \\ \frac{\qquad \qquad \qquad \qquad}{} & \frac{\qquad \qquad \qquad \qquad}{} \\ \sf 4 & \sf 0 \\ \\ \sf 4& \sf 1 \end{array}} \\ \end{gathered}$

↝ For graph see the first attachment.

━─━─━─━─━─━─━─━─━─━─━─━─━─

$\bf \:\large \red{AηsωeR : 2.} ✍$

☆The equation of line is

$\blue{\bold{\bf \:  ⟼ x + 2 = 9}}$

$\blue{\bold{\bf \:  ⟼ x = 7}}$

First, we find coordinates of points, which are lies in the line, in both x-axis & y-axis, which represents the graph structure.

➣ To calculate the coordinates of points, which are lies on the line, are shown in the below table.

$\begin{gathered}\boxed{\begin{array}{cccc}\bf x & \bf y \\ \frac{\qquad \qquad \qquad \qquad}{} & \frac{\qquad \qquad \qquad \qquad}{} \\ \sf 7 & \sf 0 \\ \\ \sf 7 & \sf 1 \end{array}} \\ \end{gathered}$

↝ For graph see the second attachment.

━─━─━─━─━─━─━─━─━─━─━─━─━─

$\bf \:\large \red{AηsωeR : 3.} ✍$

☆The equation of line is

$\purple{\bold{11y + 6 = - 27}}$

$\blue{\bold{\bf\implies \:11y = - 33}}$

$\blue{\bold{\bf \:  ⟼ y = - 3}}$

First, we find coordinates of points, which are lies in the line, in both x-axis & y-axis, which represents the graph structure.

➣ To calculate the coordinates of points, which are lies on the line, are shown in the below table.

$\begin{gathered}\boxed{\begin{array}{cccc}\bf x & \bf y \\ \frac{\qquad \qquad \qquad \qquad}{} & \frac{\qquad \qquad \qquad \qquad}{} \\ \sf 0 & \sf - 3 \\ \\ \sf 1 & \sf - 3 \end{array}} \\ \end{gathered}$

↝ For graph see the third attachment.

━─━─━─━─━─━─━─━─━─━─━─━─━─