Question

PLS SEND THE 12TH QUESTION
[URGENT]

Answer 1

Given Equation is y^3 + 13y^2 + 32y + 20.

= > y^3 + 12y^2 + y^2 + 20y + 12y + 20

= > y^3 + 12y^2 + 20y + y^2 + 12y + 20

= > y(y^2 + 12y + 20) + 1(y^2 + 12y + 20)

= > (y + 1)(y^2 + 12y + 20)

= > (y + 1)(y^2 + 2y + 10y + 20)

= > (y + 1)(y(y + 2) + 10(y + 2))

= > (y + 1)(y + 2)(y + 10).

Therefore, the factors are (y + 1)(y + 2)(y + 10).

Hope this helps!