Math, asked by evanjinvetharaja, 1 year ago

PLS SEND THE 14TH QUESTION
[URGENT]

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Answered by saliloav2003
2
1stnumber (-12)cube+(7)cube+(5)cube=0
x+y+z=0
xcube+ycube+xcube=3xyz
(-12)cube+(7)cube+(5)cube=3×(-12)×7×5=-1
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Answered by aaravshrivastwa
1

14). 1. a+b+c=0 => a³+b³+c³= 3abc  => a³+b³+c³= 3 x (-12)x7x5  => a³+be+c³= -1260   14). 2. 4x²+9y²+16z²+12xy-24yz-16xz => (2x)²+(3y)²+(4z)²+2.2x.3y+2.3y.(-4z)+2.2x.(-4z) => (2x+3y-4z)²  Be Brainly

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