Pls send the solution for 3rd question.. figure is on right side.plzzzz
Attachments:
Answers
Answered by
1
angle pQr =1/2 of POR
12*120=60 (THeroem of circle)
Pqr+psr=180 (theorem of circle)
60 + psr=180
so,psr=120
12*120=60 (THeroem of circle)
Pqr+psr=180 (theorem of circle)
60 + psr=180
so,psr=120
Urmisah62l:
Tq
Answered by
1
PQR= ½ POR { angle subtended by a chord at
the centre is double the angle subtended by it.
at circumference}
PQR = 60
PQR + PSR = 180 { sum of opposite angles in
cyclic quadrilateral is 180}
PSR = 180- 60
PSR = 120
the centre is double the angle subtended by it.
at circumference}
PQR = 60
PQR + PSR = 180 { sum of opposite angles in
cyclic quadrilateral is 180}
PSR = 180- 60
PSR = 120
Tq
wlc
Similar questions