Question

Pls send the solution for 3rd question.. figure is on right side.plzzzz

Answer 1

angle pQr =1/2 of POR
12*120=60 (THeroem of circle)

Pqr+psr=180 (theorem of circle)
60 + psr=180
so,psr=120

Answer 2

PQR= ½ POR { angle subtended by a chord at

the centre is double the angle subtended by it.

at circumference}


PQR = 60

PQR + PSR = 180 { sum of opposite angles in

cyclic quadrilateral is 180}

PSR = 180- 60

PSR = 120