Question

pls show the procedure
urgent urgent
Will surely mark as brainliest.... ​

Answer 1

Let the distance covered be x meteres.

Now speed is 1m/sec

Time = Distance/Speed

= x / 1

= x sec. ...eq. 01

Now when he walks with a speed of 3m/sec he covers 15m more which means

Speed = 3m/sec

Distance = x + 15

Time = Distance/Speed

= (x + 15 )/3 sec ...eq.02

Now Given that time taken in both cases is same so we can simply equal both equation 01 and 02.

We can solve this equation in linear equation in one variable.

$x = \frac{(x + 15)}{3} \\ \\ \\ \implies3x = x + 15 \\ \\ \\ \implies 2x = 15 \\ \\ \\ \implies \boxed{x = 7.5}$

Therefore the Orignal Distance is 7.5m.