Question

pls simple answer with explanation :)
Sodium and Chlorine react to form Sodium Chloride. If 22.99 g of sodium and 35.45 g of chlorine fully react, how much sodium chloride forms? show your work!

Answer 1

Answer:

The reaction that takes place is:

Na + Cl -> NaCl

the ratio of this reaction is 1 : 1 : 1

Na = 22.9898 g/mole

Cl = 35.453 g/mole

NaCl = 58.44 g/mole

First you calculate the mole using the known data:

mole = mass / molar mass

mole sodium = 22.99 / 22.9898 = 1.00

since the ratio is 1 : 1 : 1, all you have to do is:

mass = mole * molar mass

mass NaCl = 1.00 * 58.44 = 58.44 g

you can check if all the mass of Cl is used by calculating the mass using the mole and the molar mass:

Mass Cl = 1.00 * 35.45 = 35.45 g

Which was the amount of mass used in the reaction so everything correct, meaning the amount of mass formed in the reaction is 58.44 grams.

Explanation: