Question

pls... slove it equation and find the value of X
question ;-
$3x {}^{2} + 5 \sqrt{5x} - 10 = 0$
slove it ​

Answer 1

$heya \\ \\ 3x {}^{2} + 6 \sqrt{5}x - \sqrt{5} x - 10 = 0 \\ \\ \\ 3x(x + 2 \sqrt{5} ) - \sqrt{5} (x + 10 \div \sqrt{5} ) = 0 \\ \\ \\ \\ \\ 3x(x + 2 \sqrt{5} ) - \sqrt{5} (x + 10 \sqrt{5} \div 5) = 0 \\ \\ \\ \\ 3x(x + 2 \sqrt{5} ) - \sqrt{5} (x + 2 \sqrt{5} ) = 0 \\ \\ \\ (3x - \sqrt{5} ) = 0 \: \: \: \: or \: \: \: \: (x + 2 \sqrt{5} ) = 0 \\ \\ \\ \\ x = \sqrt{5} \div 3 \: \: \: \: \: \: or \: \: \: \: \: \: \: x = - 2 \sqrt{5}$