Question

Pls. Solve 14th and 1st question.....

Answer 1

Answer:

14th solution

cosA/1-sinA +cosA/1+sinA

take lcm

cosA +sinA.cosA +cosA -sinAcosA/1-sin^2A

2cosA/cos^2A

2/cosA

2secA

1st solution

seca =5/4 this implies sec^2a = 25/16

Tana/(1+tan^2a).

we know 1+tan^2a = sec2a. ..(1)

from here tan^2a = 25/16-1

tan^2a = 10/16

Tana = √10/4. ..(2)

put ...(1) and ..(2) in the above question

we get

$\frac{ \sqrt{10} }{4} \div \frac{25}{16} \\ \frac{ \sqrt{10} }{4} \times \frac{16}{25} \\ \frac{4 \sqrt{10} }{25}$

hope this will help you