Question

pls solve

32x + 16y = 11xy, 5x + 3y = xy

using ELIMINATION METHOD
​

Answer 1

Step-by-step explanation:

32x + 16y = 11xy -------(1)

5x +3y = xy -----------(2)

(2) × 11 =>> 55x + 33y = 11xy

32x +16y = 11xy

(2) - (1) =>> 23x +17y = 0 -----(3)

From (3) , 23x + 17y = 0

=>> 23x = -17y

=>> x = -17y/23 ----(4)

Substituting equation (3) in equation (2)

=>> 5 (-17y/23) + 3y = -17y/23 × y

=>> -85y/23 + 3y = -17y^2/23

=>> -85y + 69y/23 = -17y^2/23

=>> -16y/23 = -17y^2/23

=>> y =16/17 ----(5)

Substituting equation (5) in equation (4)

=>> x = -17/23 × 16/17

=>> x = -16/23

Therefore x =-16/23 , y = 16/17

Hope it will help you