Question

Pls solve 8q
8. Using Kirchhoff's rules in the given circuit,determine
(i) the voltage drop across the unknown resistor R and
(ii) the current I2 in the arm EF.​

Answer 1

The current I in the arm is 7/3  and the voltage drop across R is V= IR = 7/3 R Volt.

Explanation:

Using Kirchhoff’s Law to the upper portion Mesh, we have

∑IR = ∑E

1×2 – I×3 = 3-5

⇒ 2-3I = -2

⇒ -3I = -4

⇒ I = 4/3

• So, total current through R

I = 1+4/3 = 7/3

• Voltage drop across R

V= IR = 7/3 R Volt

Thus the current I in the arm is 7/3  and the voltage drop across R is V= IR = 7/3 R Volt.

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