Question

..pls solve auestion 3and 5

Answer 1

Hey there!

(3)

$( \frac{ - 1}{6} ) + \frac{3}{10}$

LCM of 6 and 10 = 30

$( \frac{ - 5}{30}) + \frac{9}{30}$

$\frac{4}{30}$

$\frac{2}{15}$

(5)

$\frac{6}{15} + ( \frac{ - 7}{25} )$

LCM of 15 and 25 = 75

$\frac{30}{75} + (\frac{ - 21}{75} )$

$\frac{9}{75}$

$\frac{3}{25}$

Hope helped.

Answer 2

Hey !!

Here is your answer..
$(1) \\ \\ = \frac{ - 1}{6} + \frac{3}{10} \\ \\ finding \: \: lcm \: \: \\ \\ = \frac{ - 1 \times 5}{30} + \frac{3 \times 3}{30} \\ \\ = \frac{ - 5 + 9}{30} \\ \\ = \frac{4}{30} \\ \\ = \frac{2}{15} \\ \\ (2) \\ \\ = \frac{6}{15} + \frac{ - 7}{25} \\ \\ finding \: \: lcm \: \: \\ \\ = \frac{6 \times 5}{75} + \frac{ - 7 \times 3}{75} \\ \\ = \frac{30 + ( - 21)}{75} \\ \\ = \frac{30 - 21}{75} \\ \\ = \frac{9}{75} \\ \\ = \frac{3}{25}$

Hope it helps you..

Thanks..