Pls solve both the questions!
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1. n(A-B) = n(A) = 10
n(B-A) = n(B) = 14
n(AUB) = 28
n(AUB) = n(A) + n(B) - n(AnB)
28=10+14 - n(AnB)
so,n(AnB)= 4
correct option is (d).
2. since, x,y€ N
and the values of y is range
so ,let us put the values of x to get the values of y
on putting values of x as 1 then we get 12
similarly on putting values of x as 2 , we get 8 and on putting values of x as 3 we get 7.
since , 7 is not present in any set of the given options except option (b), and also 8 and 12 comes under option (b).
so, the correct option is (b).
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