Math, asked by sonakshisangal, 7 months ago

pls solve briefly if it will correct I will make you brainiest​ it's urgent

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Answered by rahulanand68
0

Answer:

a) 4/7×3/5÷16/21 of 49/7×3/7

Always use the BODMAS rule here

Border , Of , Division , Multiply , Addition , Subtraction

=> 4/7×3/5÷(16/21×49/4) × 3/7

=> 4/7×3/5÷(28/3)×3/7

=> 4/7×(3/5×3/28)×3/7

=> 4/7×(9/140)×3/7

  =  > \frac{4 \times 3 \times9 }{7 \times 140 \times 7}  \\  =  >  \frac{108}{6860}

b)

4  \frac{5}{15} \div  \frac{21}{26} \times  \frac{35}{57}  \\  =  >  \frac{65}{15} \div  \frac{21}{26}   \times  \frac{35}{57}  \\  =  > ( \frac{65}{15}  \times  \frac{26}{21}) \times  \frac{35}{57}   \\  =  >  \frac{1690}{315}  \times  \frac{35}{57} \\  =  >  \frac{1690}{513}

PLS MARK AS BRAINLIST ANSWER XD

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