Pls Solve Class 10 Maths TOMORROW BOARD EXAM.....
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PM : MQ = 6:5
therefor, PM : PQ = 6: 11
As MN parallel to QR,
By BPT :
PM : PQ = MN : QR
MN : QR = 6 : 11
now in triangles MNO & RQO :
∠MON = ∠QOR (Vertically opp. angles)
∠NOM = ∠ORQ ( MN║QR, alt. interior angles )
therefore, MNO similar to RQO
therefore, ratio of areas of similar triangles is equal to ratio of sides squared.
We know MN : QR = 6 : 11,
therefore, area MNO : area QOR = MN²: QR²
= 36 : 121
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