Pls solve each of the following quadratic trinomials into factors...also tell the method to solve them...
1) -8y^2+23y+3
2) 11x^2-54x+63
Answers
Answered by
1
Heya,
Here's ur answer :-
1)-8y^2+23y+3
=-8y^2+24y-y+3
=-8y(y+3)-1(y+3)
=(-8y-1)(y+3)
=-1(8y+1)(y+3)
the answers are -1/8 and -3
2)11x^2-54x+63
=11x^2-33x-21x+63
=11x(x-3)-21(x-3)
=(x-3)(11x-21)
the answers are 3 and 21/11.
The method is that take one factor as zero and the answer will come after solving the equation. Plz check and verify
If it helped plz mark Brainliest
Here's ur answer :-
1)-8y^2+23y+3
=-8y^2+24y-y+3
=-8y(y+3)-1(y+3)
=(-8y-1)(y+3)
=-1(8y+1)(y+3)
the answers are -1/8 and -3
2)11x^2-54x+63
=11x^2-33x-21x+63
=11x(x-3)-21(x-3)
=(x-3)(11x-21)
the answers are 3 and 21/11.
The method is that take one factor as zero and the answer will come after solving the equation. Plz check and verify
If it helped plz mark Brainliest
simra1234:
the 2 answer is correct thanks alot...
Answered by
0
1) -1(8y+1)(y+3)
2) (x-3)(11x-21)
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2) (x-3)(11x-21)
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