pls solve it.. a pendulum complete two oscillations in 5 seconds .its time period is 2.5 seconds. if g is equal to 9. 8 ms - 2 find its length
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just apply formula of time period i.e
T=2pi root of l/g
T=2pi root of l/g
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fashionablegirl:
pls solve this also
1.5m
pls i want full ans
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T=2π√l/g
T²= 4π²(l/g)
l =(T²×g)/4π²
g=9.8 m/s²
l = (2.5²×9.8)/4×π²
= 3001.25/1936
=1.55m
dear i appreciate u
but it is wrong
time period is 2.5 not 5
yes
i know
oh I am sorry I had a similar question in my book so I thought it was the same
I've corrected it
ok
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