Question

pls solve it in one or two days​

Answer 1

Answer:

9/11

Hope it helps you mate

Answer 2

The value of the expression is $\frac{9}{11}$.

Step-by-step explanation:

Exponent rules:

• $(a^{m})^{n}=a^{m\times n}$
• $\sqrt[n]{a} =a^{1/n}$

The expression is:

$\frac{\sqrt[3]{27} +\sqrt[3]{8} +\sqrt[3]{64}}{\sqrt[3]{125} +\sqrt[3]{216}}$

Simplify the expression as follows:

$\frac{\sqrt[3]{27} +\sqrt[3]{8} +\sqrt[3]{64}}{\sqrt[3]{125} +\sqrt[3]{216}}=[\sqrt[3]{27} +\sqrt[3]{8} +\sqrt[3]{64}]\div[\sqrt[3]{125} +\sqrt[3]{216}]$

                    $=[(3^{3})^{1/3}+(2^{3})^{1/3}+(4^{3})^{1/3}]\div[(5^{3})^{1/3}+(6^{3})^{1/3}]\\=[3+2+4]\div[5+6]\\=9\div11$

                    $=\frac{9}{11}$

Thus, the value of the expression is $\frac{9}{11}$.