Math, asked by mooonaaaaaaa, 1 month ago

pls solve it
it's urgent ​

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Answers

Answered by sirireddykristipati
0

Answer:

answer is 1.

look at the picture for explantion.

I hope it may help you

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Answered by Salmonpanna2022
1

Step-by-step explanation:

Here is your answer friend.

Question:-

 \bigg( \frac{81}{16}  \bigg)^{  - 3/4  }  \times \left\{ \bigg( \frac{25}{9}  \bigg)^{ - 3/2}  \div  \bigg( \frac{5}{2}  \bigg) ^{ - 3} \right\} \\  \\

What to do:

To simplify.

Solution:-

Let's solve the given problem

We have,

 \bigg( \frac{81}{16}  \bigg)^{  - 3/4  }  \times \left\{ \bigg( \frac{25}{9}  \bigg)^{ - 3/2}  \div  \bigg( \frac{5}{2}  \bigg) ^{ - 3} \right\} \\  \\

⟹ \bigg( \frac{16}{81}  \bigg)^{  3/4  }  \times \left\{ \bigg( \frac{9}{25}  \bigg)^{3/2}  \div  \bigg( \frac{2}{5}  \bigg) ^{ 3} \right\} \\  \\

⟹ \bigg( \frac{ {2}^{4} }{ {3}^{4} }  \bigg)^{  3/4  }  \times \left\{ \bigg( \frac{ {3}^{2} }{ {5}^{2} }  \bigg)^{3/2}  \div  \bigg( \frac{2}{5}  \bigg) ^{ 3} \right\} \\  \\

⟹ \bigg( \frac{2}{3}  \bigg)^{ \cancel{4 }\times   3/ \cancel{4}  }  \times \left\{ \bigg( \frac{3}{5}  \bigg)^{ \cancel{2 }\times 3/ \cancel{2}}  \div  \bigg( \frac{2}{5}  \bigg) ^{ 3} \right\} \\  \\

⟹ \bigg( \frac{2}{3}  \bigg)^{  3 }  \times \left\{ \bigg( \frac{3}{5}  \bigg)^{3}   \times   \bigg( \frac{5}{2}  \bigg) ^{ 3} \right\} \\  \\

⟹ \bigg( \frac{2}{3}  \bigg)^{  3 }  \times \bigg(  \frac{ {3}^{3} } { \cancel{ {5}^{3}} }  \times  \frac{  \cancel{{5}^{3}} }{ {2}^{3} } \bigg) \\  \\

⟹ \bigg( \frac{2}{3}  \bigg)^{  3 }  \times \bigg( \frac{3}{2}  \bigg)^{  3 }  \\  \\

⟹ \frac{  \cancel{{2}^{3}} }{  \cancel{{3}^{3} }}  \times  \frac{ \cancel{ {3}^{3}} }{  \cancel{{2}^{3}} }  \\

⟹1.Ans  \\  \\

Answer:-

  • 1

More information:-

Low of Integral Exponents

For any two real numbers a and b, a, b ≠ 0, and for any two positive integers, m and n

➲ If a be any non - zero rational number, then

  • a^0 = 1

➲ If a be any non - zero rational number and m,n be integer, then

  • (a^m)^n = a^mn

➲ If a be any non - zero rational number and m be any positive integer, then

  • a^-m = 1/a^m

➲ If a/b is a rational number and m is a positive integer, then

  • (a/b)^m = a^m/b^m

➲ For any Integers m and n and any rational number a, a ≠ 0

  • a^m × a^n = a^m+n

➲ For any Integers m and n for non - zero rational number a,

  • a^m ÷ a^n = a^m-n

➲ If a and b are non - zero rational numbers and m is any integer, then

  • (a+b)^m = a^m × b^m

  • I hope it's help you...☺

:)

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