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Answers
GIVEN :-
Dimensions of surface block A = 10 cm × 5 cm
Dimensions of surface block B = 5 cm × 5 cm
Dimensions of surface block C = 20 cm × 10 cm
Dimensions of surface block D = 5 cm × 2 cm
Masses of all the blocks are same. (Let it be m)
TO FIND :-
On which block's surface, will the pressure be maximum.
ACKNOWLEDGEMENT :-
- Force = mass × acceleration
→ Acceleration(g) = 10 m/s²
- Pressure = Force/Area
SOLUTION :-
For block A,
Force = ma
⇒F = 10m
Area = 10 × 5 = 50 m²
Pressure = Force/Area
⇒P = 10m/50
⇒P = m/5 ...(i)
For block B,
Force = ma
⇒F = 10m
Area = 5 × 5 = 25 cm²
Pressure = Force/Area
⇒P = 10m/25
⇒P = 2m/5 ...(ii)
For block C,
Force = ma
⇒F = 10m
Area = 20 × 10 = 200 cm²
Pressure = Force/Area
⇒P = 10m/200
⇒P = m/20 ...(iii)
For block D,
Force = ma
⇒F = 10m
Area = 5 × 2 = 10 m²
Pressure = Force/Area
⇒P = 10m/10
⇒P = m ...(iv)
Comparing equations (i), (ii), (iii) and (iv), we conclude that pressure on the surface of block D is the highest.
Therefore, the answer is (4) D.
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