Physics, asked by avani1396, 8 months ago

pls solve it no spam... I post 1 question 2 times... because of ur spam... so pls.. understand...


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Answers

Answered by CunningKing
3

GIVEN :-

Dimensions of surface block A = 10 cm × 5 cm

Dimensions of surface block B = 5 cm × 5 cm

Dimensions of surface block C = 20 cm × 10 cm

Dimensions of surface block D = 5 cm × 2 cm

Masses of all the blocks are same. (Let it be m)

TO FIND :-

On which block's surface, will the pressure be maximum.

ACKNOWLEDGEMENT :-

  • Force = mass × acceleration

→ Acceleration(g) = 10 m/s²

  • Pressure = Force/Area

SOLUTION :-

For block A,

Force = ma

⇒F = 10m

Area = 10 × 5 = 50 m²

Pressure = Force/Area

⇒P = 10m/50

⇒P = m/5                  ...(i)

\rule{150}{1}

For block B,

Force = ma

⇒F = 10m

Area = 5 × 5 = 25 cm²

Pressure = Force/Area

⇒P = 10m/25

⇒P = 2m/5               ...(ii)

\rule{150}{1}

For block C,

Force = ma

⇒F = 10m

Area = 20 × 10 = 200 cm²

Pressure = Force/Area

⇒P = 10m/200

⇒P = m/20               ...(iii)

\rule{150}{1}

For block D,

Force = ma

⇒F = 10m

Area = 5 × 2 = 10 m²

Pressure = Force/Area

⇒P = 10m/10

⇒P = m                 ...(iv)

\rule{150}{1}

Comparing equations (i), (ii), (iii) and (iv), we conclude that pressure on the surface of block D is the highest.

Therefore, the answer is (4) D.

Answered by Anonymous
1

nice question...........missing uh❤

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