Pls solve it now i am waiting
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Step-by-step explanation:
See it is example so solution is there
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Answer:
In ∆ ABF AND ∆ ACE
AB=AC (GIVEN)
ANGLE A = ANGLE A. (COMMON)
AF=AE. (HAVLES OF EQUAL SIDES)
∆ ABF ~ =∆ACE
BF = CE (CPCT)
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