Math, asked by sanyogitasinghbgm, 9 months ago

pls solve it...pls i need the ans....pls....​

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Answers

Answered by rashmijaiswal2008
1

Answer:

AD=60cm, BC=24cm, radius of smaller circle=20 cm

Step-by-step explanation:

Given OA=34cm OP=16cm

Using pythagoras theorem

OA square=OP square+AP square

34 square=16 square+ AP square

AP square=34 square-16 square

AP square=900

AP=30 cm

AD=2AP=2×30 =60 cm

BP=AP-AB=30-18=12cm

BC=2BP=2×12=24 cm

BP=12cm, OP=16cm

OB is the hypotenuse of triangle OBP and also radius of the small circle.

By pythagoras theorem

OB square=OP square+BP square

OB square=16 square+12 square

OB square=400

OB=20 cm

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