pls solve it...pls i need the ans....pls....
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Answer:
AD=60cm, BC=24cm, radius of smaller circle=20 cm
Step-by-step explanation:
Given OA=34cm OP=16cm
Using pythagoras theorem
OA square=OP square+AP square
34 square=16 square+ AP square
AP square=34 square-16 square
AP square=900
AP=30 cm
AD=2AP=2×30 =60 cm
BP=AP-AB=30-18=12cm
BC=2BP=2×12=24 cm
BP=12cm, OP=16cm
OB is the hypotenuse of triangle OBP and also radius of the small circle.
By pythagoras theorem
OB square=OP square+BP square
OB square=16 square+12 square
OB square=400
OB=20 cm
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