Math, asked by Anonymous, 9 months ago

☄️pls solve it's argent ☄️

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Answered by khushi02022010
14

Answer:

Proof:

Suppose points A, B, C, D are not concyclic points.

We can still draw a circle passing through three non collinear points A, B, D.

Case I: Point C lies outside the circle.

Then, take point E on the circle such that

A – E – C.

∠ABD ≅ ∠AED (i) [Angles inscribed in the same arc]

∠ABD ≅ ∠ACD (ii) [Given]

∴ ∠AED ≅ ∠ACD [From (i) and (ii)]

∴ ∠AED ≅ ∠ECD [A – E – C]

But, ∠AED ≅ ∠ECD as ∠AED is the exterior angle of ∆ECD.

∴ Our supposition is wrong.

∴ Points A, B, C, D are concyclic points.

Case II: Point C lies inside the circle. Then, take point E on the circle such that A – C – E.

∠ABD ≅ ∠AED (iii) [Angles inscribed in the same arc]

∠ABD ≅ ∠ACD (iv) [Given]

∴ ∠AED ≅ ∠ACD [From (iii) and (iv)]

∴ ∠CED ≅ ∠ACD [A – C – E]

Answered by Anonymous
6

on 1st April, 2015A sold a machinery on hire-purchase to B, the cash price being ₹1000. the hire - purchase agrees to pay in two instalments of ₹500each yearly. The interest is 5%per annum. Show B's account in A's book.

RAKESH IT IS THE ANSWER FOR YOUR PREVIOUS QUESTION. I HOPE IT HELPS. ☺

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