pls solve it very urgent
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now clear, ................
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Let one zero of the given polynomial be à then the other zero is 1/à
Given polynomial,
(a²+a)n² + 13n + 6a
We know that,
Product of zeroes = constant/n² coefficient
à × 1/à = 6a/(a²+a)
6a/(a²+a) = 1
6a = a² + a
5a = a²
5a - a² = 0
a(5-a) = 0
5-a = 0
» a = 5
Therefore, the value of a is 5.
Hope it helps.......
Given polynomial,
(a²+a)n² + 13n + 6a
We know that,
Product of zeroes = constant/n² coefficient
à × 1/à = 6a/(a²+a)
6a/(a²+a) = 1
6a = a² + a
5a = a²
5a - a² = 0
a(5-a) = 0
5-a = 0
» a = 5
Therefore, the value of a is 5.
Hope it helps.......
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